1.
Let AA be a matrix of order 3×33 \times 3 and A=5|A| = 5. If 2adj(3Aadj(2A))=2α3β5γ,  α,β,γN|2\,\text{adj}(3A\,\text{adj}(2A))| = 2^{\alpha} \cdot 3^{\beta} \cdot 5^{\gamma}, \; \alpha, \beta, \gamma \in \mathbb{N}, then α+β+γ\alpha + \beta + \gamma is equal to: