1.If zzz is a complex number, then the number of common roots of the equation z1985+z100+1=0z^{1985} + z^{100} + 1 = 0z1985+z100+1=0 and z3+2z2+2z+1=0z^3 + 2z^2 + 2z + 1 = 0z3+2z2+2z+1=0, is equal to:a.111b.222c.000d.333Login to continueOnly logged in users canattempt or see the solution.
