1.Let α,β\alpha, \betaα,β be the roots of the equation x2−2x+2=0x^2 - \sqrt{2} x + 2 = 0x2−2x+2=0. Then α14+β14\alpha^{14} + \beta^{14}α14+β14 is equal toa.−64-64−64b.−642-64\sqrt{2}−642c.128128128d.−1282-128\sqrt{2}−1282Login to continueOnly logged in users canattempt or see the solution.
