1.Let f,g:R→Rf, g: \mathbb{R} \to \mathbb{R}f,g:R→R be defined as f(x)=∣x−1∣f(x) = |x-1|f(x)=∣x−1∣ and g(x)={ex,x≥0x+1,x≤0g(x) = \begin{cases} e^x, & x \ge 0 \\ x+1, & x \le 0 \end{cases}g(x)={ex,x+1,x≥0x≤0 Then the function f(g(x))f(g(x))f(g(x)) is:Login to continueOnly logged in users canattempt or see the solution.
