1.limx→∞11/x+21/x+31/x+…+n1/xn\displaystyle \lim_{x \to \infty} \frac{1^{1/x} + 2^{1/x} + 3^{1/x} + \ldots + n^{1/x}}{n}x→∞limn11/x+21/x+31/x+…+n1/x (where n∈Nn \in \mathbb{N}n∈N) is equal toa.n!n!n!b.111c.1n!\displaystyle \frac{1}{n!}n!1d.000Login to continueOnly logged in users canattempt or see the solution.