1.If the mean and standard deviation of 555 observations x1,x2,x3,x4,x5x_1, x_2, x_3, x_4, x_5x1,x2,x3,x4,x5 are 101010 and 333, respectively, then the variance of 666 observations x1,x2,…,x5x_1, x_2, \ldots, x_5x1,x2,…,x5 and −50-50−50 is equal to:a.582.5582.5582.5b.507.5507.5507.5c.509.5509.5509.5d.586.5586.5586.5Login to continueOnly logged in users canattempt or see the solution.