1.The equation of plane containing line x−y=1x - y = 1x−y=1, z=1z = 1z=1 and parallel to x2−z3=1\frac{x}{2} - \frac{z}{3} = 12x−3z=1, y=3y = 3y=3 isa.3x+3y−2z=13x + 3y - 2z = 13x+3y−2z=1b.3x−3y−2z=13x - 3y - 2z = 13x−3y−2z=1c.3x+3y+2z=13x + 3y + 2z = 13x+3y+2z=1d.3x+3y+2z=−13x + 3y + 2z = -13x+3y+2z=−1Login to continueOnly logged in users canattempt or see the solution.
