1.CH4→Cl2/hv(A)→KCN, acetone(B)→SnCl2, HCl(C)→H3O+(D)\text{CH}_4 \xrightarrow{\text{Cl}_2/\text{hv}} (A) \xrightarrow{\text{KCN, acetone}} (B) \xrightarrow{\text{SnCl}_2,\,\text{HCl}} (C) \xrightarrow{\text{H}_3\text{O}^+} (D)CH4Cl2/hv(A)KCN, acetone(B)SnCl2,HCl(C)H3O+(D)Product D will be:a.CH3CH2CHO\text{CH}_3\text{CH}_2\text{CHO}CH3CH2CHOb.CH3CH=NH\text{CH}_3\text{CH}=\text{NH}CH3CH=NHc.CH3CHO\text{CH}_3\text{CHO}CH3CHOd.CH3COOH\text{CH}_3\text{COOH}CH3COOHLogin to continueOnly logged in users canattempt or see the solution.
