1.Let f(x)=min{1, 1+xsinx}f(x) = \min\{1,\; 1 + x\sin x\}f(x)=min{1,1+xsinx}, 0≤x≤2π0 \leq x \leq 2\pi0≤x≤2π. If mmm is the number of points where fff is not differentiable and nnn is the number of points where fff is not continuous, then the ordered pair (m,n)(m,n)(m,n) is equal toLogin to continueOnly logged in users canattempt or see the solution.