1.If the Boolean expression (p⊕q)∧(¬p⊙q)(p \oplus q) \land (\neg p \odot q)(p⊕q)∧(¬p⊙q) is equivalent to p∧qp \land qp∧q, where ⊕,⊙∈{∧,∨}\oplus, \odot \in \{\land, \lor\}⊕,⊙∈{∧,∨}, then the ordered pair (⊕,⊙)(\oplus, \odot)(⊕,⊙) isa.(∨,∧)(\lor, \land)(∨,∧)b.(∧,∧)(\land, \land)(∧,∧)c.(∨,∨)(\lor, \lor)(∨,∨)d.(∧,∨)(\land, \lor)(∧,∨)Login to continueOnly logged in users canattempt or see the solution.
