1.If the coefficient of x7x^7x7 in (ax2+1bx)11\left(ax^2 + \dfrac{1}{bx}\right)^{11}(ax2+bx1)11 and the coefficient of x−7x^{-7}x−7 in (ax−1bx2)11\left(ax - \dfrac{1}{bx^2}\right)^{11}(ax−bx21)11 are equal, then:a.729ab=32729ab = 32729ab=32b.32ab=72932ab = 72932ab=729c.64ab=24364ab = 24364ab=243d.243ab=64243ab = 64243ab=64Login to continueOnly logged in users canattempt or see the solution.