1.Let a∈Ra \in \mathbb{R}a∈R and AAA be a matrix of order 3×33 \times 33×3 such that det(A)=4\det(A) = 4det(A)=4 andA+I=(1201a1a12),A + I = \begin{pmatrix} 1 & 2 & 0 \\ 1 & a & 1 \\ a & 1 & 2 \end{pmatrix},A+I=11a2a1012,where III is the identity matrix of order 3×33 \times 33×3. If det((a+1) adj((a−1)A))=2m⋅3n, m,n∈{0,1,2,…,20}\det\left((a+1)\,\text{adj}\left((a-1)A\right)\right) = 2^{m} \cdot 3^{n}, \; m, n \in \{0,1,2,\ldots,20\}det((a+1)adj((a−1)A))=2m⋅3n,m,n∈{0,1,2,…,20}, then m+nm + nm+n is equal to:a.141414b.171717c.151515d.161616Login to continueOnly logged in users canattempt or see the solution.