1.If f(x)=x2−bx+25x2−7x+10f(x) = \dfrac{x^2 - bx + 25}{x^2 - 7x + 10}f(x)=x2−7x+10x2−bx+25 for x≠5x \neq 5x=5 and fff is continuous at x=5x = 5x=5, then f(5)f(5)f(5) has the value equal to:a.000b.555c.101010d.252525Login to continueOnly logged in users canattempt or see the solution.
