1.If 101010 different balls are placed in 444 distinct boxes at random, then the probability that two of these boxes contain exactly 222 and 333 balls is:a.9051024\dfrac{905}{1024}1024905b.9101024\dfrac{910}{1024}1024910c.9451024\dfrac{945}{1024}1024945d.9651024\dfrac{965}{1024}1024965Login to continueOnly logged in users canattempt or see the solution.
