1.Let x,y>0x, y > 0x,y>0. If x3y2=215x^3 y^2 = 2^{15}x3y2=215, then the least value of 3x+2y3x + 2y3x+2y isa.30b.32c.36d.40Login to continueOnly logged in users canattempt or see the solution.
