1.Degree of dissociation of 0.1 N0.1\,\text{N}0.1N CH3COOH\text{CH}_3\text{COOH}CH3COOH is (dissociation constant Ka=1×10−5K_a = 1 \times 10^{-5}Ka=1×10−5):a.10−510^{-5}10−5b.10−410^{-4}10−4c.10−310^{-3}10−3d.10−210^{-2}10−2Login to continueOnly logged in users canattempt or see the solution.
