1.The common difference of the A.P. b1,b2,…,bmb_1, b_2, \ldots, b_mb1,b2,…,bm is 2 more than the common difference of A.P. a1,a2,…,ana_1, a_2, \ldots, a_na1,a2,…,an. If a40=−159a_{40} = -159a40=−159, a100=−399a_{100} = -399a100=−399 and b100=a70b_{100} = a_{70}b100=a70, then b1b_1b1 is equal to:a.818181b.−127-127−127c.−81-81−81d.127127127Login to continueOnly logged in users canattempt or see the solution.
