1.The particular solution of the differential equation sin2ydxdy+x=coty\sin^2 y \frac{dx}{dy} + x = \cot ysin2ydydx+x=coty when x=0x = 0x=0 and y=3π4y = \frac{3\pi}{4}y=43π isa.x=1+cotyx = 1 + \cot yx=1+cotyb.xy=cot(x+y)xy = \cot(x + y)xy=cot(x+y)c.xy=cot(x−y)xy = \cot(x - y)xy=cot(x−y)d.y=1+cotxy = 1 + \cot xy=1+cotxLogin to continueOnly logged in users canattempt or see the solution.