1.If (3+i)100=299(p+iq)(\sqrt{3} + i)^{100} = 2^{99}(p + iq)(3+i)100=299(p+iq), then ppp and qqq are roots of the equation:a.x2−(3+1)x+3=0x^2 - (\sqrt{3} + 1)x + \sqrt{3} = 0x2−(3+1)x+3=0b.x2+(3+1)x+3=0x^2 + (\sqrt{3} + 1)x + \sqrt{3} = 0x2+(3+1)x+3=0c.x2+(3−1)x−3=0x^2 + (\sqrt{3} - 1)x - \sqrt{3} = 0x2+(3−1)x−3=0d.x2−(3−1)x−3=0x^2 - (\sqrt{3} - 1)x - \sqrt{3} = 0x2−(3−1)x−3=0Login to continueOnly logged in users canattempt or see the solution.
