1.Two resistances are measured in ohm and are given as: R1=3 Ω±1%R_1 = 3\,\Omega \pm 1\%R1=3Ω±1%, R2=6 Ω±2%R_2 = 6\,\Omega \pm 2\%R2=6Ω±2%. When they are connected in parallel, the percentage error in equivalent resistance isa.3%3\%3%b.4.5%4.5\%4.5%c.0.67%0.67\%0.67%d.1.33%1.33\%1.33%Login to continueOnly logged in users canattempt or see the solution.