1.If α\alphaα and β\betaβ be two roots of the equation x2−64x+256=0x^2 - 64x + 256 = 0x2−64x+256=0, then the value of (αβ)1/2+(βα)1/2\left(\dfrac{\alpha}{\beta}\right)^{1/2} + \left(\dfrac{\beta}{\alpha}\right)^{1/2}(βα)1/2+(αβ)1/2 is:a.222b.333c.111d.444Login to continueOnly logged in users canattempt or see the solution.
