1.Consider the following processes:12A→B\frac{1}{2}A \rightarrow B21A→B; ΔH=+150 kJ mol−1\Delta H = +150\,\text{kJ mol}^{-1}ΔH=+150kJ mol−13B→2C+D3B \rightarrow 2C + D3B→2C+D; ΔH=−125 kJ mol−1\Delta H = -125\,\text{kJ mol}^{-1}ΔH=−125kJ mol−1E+A→2DE + A \rightarrow 2DE+A→2D; ΔH=+350 kJ mol−1\Delta H = +350\,\text{kJ mol}^{-1}ΔH=+350kJ mol−1For B+D→E+2CB + D \rightarrow E + 2CB+D→E+2C, ΔH\Delta HΔH will be:a.525 kJ mol−1525\,\text{kJ mol}^{-1}525kJ mol−1b.−175 kJ mol−1-175\,\text{kJ mol}^{-1}−175kJ mol−1c.−325 kJ mol−1-325\,\text{kJ mol}^{-1}−325kJ mol−1d.325 kJ mol−1325\,\text{kJ mol}^{-1}325kJ mol−1Login to continueOnly logged in users canattempt or see the solution.
