1.A straight line L through the point (3,−2)(3, -2)(3,−2) is inclined at an angle 60∘60^\circ60∘ to the line 3x+y=1\sqrt{3}x + y = 13x+y=1. If L also intersects the X-axis, then the equation of L isa.y+3x+2−33=0y + \sqrt{3}x + 2 - 3\sqrt{3} = 0y+3x+2−33=0b.y−3x+2+33=0y - \sqrt{3}x + 2 + 3\sqrt{3} = 0y−3x+2+33=0c.3y−x+3+23=0\sqrt{3}y - x + 3 + 2\sqrt{3} = 03y−x+3+23=0d.3y+x−3+23=0\sqrt{3}y + x - 3 + 2\sqrt{3} = 03y+x−3+23=0Login to continueOnly logged in users canattempt or see the solution.
