1.If xxx, yyy, zzz are in arithmetic progression and tan−1x\tan^{-1}xtan−1x, tan−1y\tan^{-1}ytan−1y and tan−1z\tan^{-1}ztan−1z are also in arithmetic progression, thena.x=y=zx = y = zx=y=zb.x=y=−zx = y = -zx=y=−zc.x=1x = 1x=1, y=2y = 2y=2, z=3z = 3z=3d.x=2x = 2x=2, y=4y = 4y=4, z=6z = 6z=6Login to continueOnly logged in users canattempt or see the solution.
