1.If the functionf(x)={1xloge(1+xa1−xb),x<0k,x=0cos2x−sin2x−1x2+1−1,x>0f(x) = \begin{cases} \frac{1}{x} \log_e\left(\frac{1 + \frac{x}{a}}{1 - \frac{x}{b}}\right), & x < 0 \\ k, & x = 0 \\ \frac{\cos^2 x - \sin^2 x - 1}{\sqrt{x^2 + 1} - 1}, & x > 0 \end{cases}f(x)=⎩⎨⎧x1loge(1−bx1+ax),k,x2+1−1cos2x−sin2x−1,x<0x=0x>0is continuous at x=0x = 0x=0, then 1a+1b+4k\frac{1}{a} + \frac{1}{b} + \frac{4}{k}a1+b1+k4 is equal to:Login to continueOnly logged in users canattempt or see the solution.