1.A ball is projected from a point in a horizontal plane and makes one rebound. If the second range is equal to the greatest height, thena.Angle of projection α=tan−1(4)\alpha = \tan^{-1}(4)α=tan−1(4)b.Angle of projection α=tan−1(4e)\alpha = \tan^{-1}(4e)α=tan−1(4e), where eee is the coefficient of restitutionc.Angle of projection is 45∘45^\circ45∘d.The greatest height =eu2sin2α2g= \dfrac{e u^2 \sin^2\alpha}{2g}=2geu2sin2αLogin to continueOnly logged in users canattempt or see the solution.
