1.A spherical balloon is being inflated at the rate of 35 cc/min. The rate of increase in the surface area (in cm2^22/min.) of the balloon when its diameter is 14 cm, is: (Use π=227\pi=\frac{22}{7}π=722)a.10\sqrt{10}10b.101010\sqrt{10}1010c.100d.10Login to continueOnly logged in users canattempt or see the solution.