1.If equation of transverse wave is y=x0cos2π(nt−xλ)y = x_0 \cos 2\pi\left(nt - \frac{x}{\lambda}\right)y=x0cos2π(nt−λx). Maximum velocity of particle is twice of wave velocity, if λ\lambdaλ isa.π/2x0\pi/2x_0π/2x0b.2πx02\pi x_02πx0c.π\piπd.πx0\pi x_0πx0Login to continueOnly logged in users canattempt or see the solution.
