1.The value of limx→1−2π−4sin−1x1−x\displaystyle\lim_{x\to1^-}\frac{\sqrt{2\pi}-\sqrt{4\sin^{-1}x}}{\sqrt{1-x}}x→1−lim1−x2π−4sin−1x is equal toa.π\sqrt\piπb.1/2π1/\sqrt{2\pi}1/2πc.π/2\sqrt{\pi/2}π/2d.2/π2/\sqrt\pi2/πLogin to continueOnly logged in users canattempt or see the solution.
