1.Transverse axis =6=6=6, latus rectum =8/3=8/3=8/3. Equation of hyperbola isa.4x2−9y2=724x^2 - 9y^2 = 724x2−9y2=72b.4x2−9y2=364x^2 - 9y^2 = 364x2−9y2=36c.9x2−4y2=729x^2 - 4y^2 = 729x2−4y2=72d.9x2−4y2=369x^2 - 4y^2 = 369x2−4y2=36Login to continueOnly logged in users canattempt or see the solution.
