1.If in the expansion of (a−2b)n(a - 2b)^n(a−2b)n, the sum of the 5th and 6th term is zero, then the value of ab\frac{a}{b}ba isa.n−45\frac{n-4}{5}5n−4b.2(n−4)5\frac{2(n-4)}{5}52(n−4)c.5n−4\frac{5}{n-4}n−45d.52(n−4)\frac{5}{2(n-4)}2(n−4)5Login to continueOnly logged in users canattempt or see the solution.
