1.CH2=CH-CH(D)(CH3)→HBr/CCl4\text{CH}_2\text{=CH-CH(D)(CH}_3\text{)} \xrightarrow{\text{HBr}/\text{CCl}_4}CH2=CH-CH(D)(CH3)HBr/CCl4 Product (without rearrangement of carbocation). What is the stereochemistry of the product formed?a.Racemic mixtureb.Optically inactivec.Mixture of diastereomersd.Meso productLogin to continueOnly logged in users canattempt or see the solution.
