1.The point of the curve y2=2(x−3)y^2 = 2(x - 3)y2=2(x−3) at which the normal is parallel to the line y−2x+1=0y - 2x + 1 = 0y−2x+1=0 isa.(5,2)(5, 2)(5,2)b.(5,−2)(5, -2)(5,−2)c.(52,−2)(\frac{5}{2}, -2)(25,−2)d.(52,2)(\frac{5}{2}, 2)(25,2)Login to continueOnly logged in users canattempt or see the solution.
