1.LetA=(22+p2+p+q46+2p8+3p+2q612+3p20+6p+3q).A = \begin{pmatrix} 2 & 2+p & 2+p+q \\ 4 & 6+2p & 8+3p+2q \\ 6 & 12+3p & 20+6p+3q \end{pmatrix}.A=2462+p6+2p12+3p2+p+q8+3p+2q20+6p+3q.If det(adj(adj(3A)))=2m⋅3n, m,n∈N\det(\text{adj}(\text{adj}(3A))) = 2^{m} \cdot 3^{n}, \; m, n \in \mathbb{N}det(adj(adj(3A)))=2m⋅3n,m,n∈N, then m+nm + nm+n is equal to:a.222222b.242424c.262626d.202020Login to continueOnly logged in users canattempt or see the solution.
