1.A car is moving along a circular track with tangential acceleration of magnitude α\alphaα. It just starts to slip at speed v0v_0v0. Find the radius of the circle. (Coefficient of friction is μ\muμ.)a.r=v02(μg)2+α2r = \dfrac{v_0^2}{\sqrt{(\mu g)^2 + \alpha^2}}r=(μg)2+α2v02b.r=v02(μg)2−α2r = \dfrac{v_0^2}{\sqrt{(\mu g)^2 - \alpha^2}}r=(μg)2−α2v02c.r=v02(μg)2−2α2r = \dfrac{v_0^2}{\sqrt{(\mu g)^2 - 2\alpha^2}}r=(μg)2−2α2v02d.r=v02(μg)2+2α2r = \dfrac{v_0^2}{\sqrt{(\mu g)^2 + 2\alpha^2}}r=(μg)2+2α2v02Login to continueOnly logged in users canattempt or see the solution.