1.Let S={x∈[−6,3]−{−2,2}:∣x+3∣−1∣x−2∣≥0}S = \{x \in [-6, 3] - \{-2, 2\} : \frac{|x+3| - 1}{|x-2|} \geq 0\}S={x∈[−6,3]−{−2,2}:∣x−2∣∣x+3∣−1≥0} andT={x∈Z:x2−7∣x∣+9≤0}T = \{x \in \mathbb{Z} : x^2 - 7|x| + 9 \leq 0\}T={x∈Z:x2−7∣x∣+9≤0}.Then the number of elements in S∩TS \cap TS∩T is:a.7b.5c.4d.3Login to continueOnly logged in users canattempt or see the solution.
