1.If x+iy−23i=u+iv\frac{x+iy-2}{3i} = u + iv3ix+iy−2=u+iv, then y=y =y=a.9uu2+v2\frac{9u}{u^2+v^2}u2+v29ub.3uu2+v2\frac{3u}{u^2+v^2}u2+v23uc.6uu2+v2\frac{6u}{u^2+v^2}u2+v26ud.12uu2+v2\frac{12u}{u^2+v^2}u2+v212uLogin to continueOnly logged in users canattempt or see the solution.
