1.Circle through foci of x216+y29=1\frac{x^2}{16}+\frac{y^2}{9}=116x2+9y2=1, centre (0,3)(0,3)(0,3) isa.x2+y2−6y−5=0x^2+y^2-6y-5=0x2+y2−6y−5=0b.x2+y2−6y+5=0x^2+y^2-6y+5=0x2+y2−6y+5=0c.x2+y2−6y−7=0x^2+y^2-6y-7=0x2+y2−6y−7=0d.x2+y2−6y+7=0x^2+y^2-6y+7=0x2+y2−6y+7=0Login to continueOnly logged in users canattempt or see the solution.
