1.ABC is a right-angled triangle in which max{AB, BC, AC} = BC. If the position vectors of B and C are respectively 3i^−2j^+k^3\hat{i} - 2\hat{j} + \hat{k}3i^−2j^+k^ and 5i^+j^−3k^5\hat{i} + \hat{j} - 3\hat{k}5i^+j^−3k^, then AB→⋅AC→+BA→⋅BC→+CA→⋅CB→=\overrightarrow{AB} \cdot \overrightarrow{AC} + \overrightarrow{BA} \cdot \overrightarrow{BC} + \overrightarrow{CA} \cdot \overrightarrow{CB} =AB⋅AC+BA⋅BC+CA⋅CB=a.282828b.292929c.272727d.252525Login to continueOnly logged in users canattempt or see the solution.