1.The distance of the point (−1,−5,−10)(-1,-5,-10)(−1,−5,−10) from the point of intersection of the line x−22=y+14=z−212\displaystyle\frac{x-2}{2}=\frac{y+1}{4}=\frac{z-2}{12}2x−2=4y+1=12z−2 and the plane x−y+z=5x-y+z=5x−y+z=5 isa.11\sqrt{11}11b.126\sqrt{126}126c.131313d.141414Login to continueOnly logged in users canattempt or see the solution.
