1.The quadratic equation 2x2−(a3+8a−1)x+a2−4a=02x^2 - (a^3 + 8a - 1)x + a^2 - 4a = 02x2−(a3+8a−1)x+a2−4a=0 has roots of opposite sign. Then,a.a≤0a \le 0a≤0b.0<a<40 < a < 40<a<4c.4≤a<84 \le a < 84≤a<8d.a≥8a \ge 8a≥8Login to continueOnly logged in users canattempt or see the solution.
