1.The value of limx→−∞(4x2−x+2x)\displaystyle\lim_{x\to-\infty}\left(\sqrt{4x^2-x}+2x\right)x→−∞lim(4x2−x+2x) isa.−∞-\infty−∞b.−1/4-1/4−1/4c.000d.1/41/41/4Login to continueOnly logged in users canattempt or see the solution.
