1.The value of λ\lambdaλ for which the straight line x−λ3=y−12+λ=z−3−1\frac{x-\lambda}{3} = \frac{y-1}{2+\lambda} = \frac{z-3}{-1}3x−λ=2+λy−1=−1z−3 may lie on the plane x−2y=0x - 2y = 0x−2y=0, isa.2b.0c.−12-\frac{1}{2}−21d.there is no such λ\lambdaλLogin to continueOnly logged in users canattempt or see the solution.
