1.Let PPP be the mid-point of a chord joining the vertex of the parabola y2=8xy^2 = 8xy2=8x to another point on it. Then, the locus of PPP isa.y2=2xy^2 = 2xy2=2xb.y2=4xy^2 = 4xy2=4xc.x24+y2=1\frac{x^2}{4} + y^2 = 14x2+y2=1d.x2+y24=1x^2 + \frac{y^2}{4} = 1x2+4y2=1Login to continueOnly logged in users canattempt or see the solution.
