1.If S={z∈C:∣z−i∣=∣z+i∣=∣z−1∣}S = \{z \in \mathbb{C} : |z - i| = |z + i| = |z - 1|\}S={z∈C:∣z−i∣=∣z+i∣=∣z−1∣}, then n(S)n(S)n(S) is:a.111b.000c.333d.222Login to continueOnly logged in users canattempt or see the solution.
