1.If the coefficients of x2x^2x2 and x3x^3x3 are both zero, in the expansion of the expression (1+ax+bx2)(1−3x)15(1 + ax + bx^2)(1 - 3x)^{15}(1+ax+bx2)(1−3x)15 in powers of xxx, then the ordered pair (a,b)(a, b)(a,b) is equal toa.(28,315)(28, 315)(28,315)b.(−21,714)(-21, 714)(−21,714)c.(28,861)(28, 861)(28,861)d.(−54,315)(-54, 315)(−54,315)Login to continueOnly logged in users canattempt or see the solution.