1.The solution of the differential equation dydx=(x+y)2\frac{dy}{dx} = (x + y)^2dxdy=(x+y)2 isa.tan−1(x+y)=x+C\tan^{-1}(x + y) = x + Ctan−1(x+y)=x+Cb.tan−1(x+y)=0\tan^{-1}(x + y) = 0tan−1(x+y)=0c.cot−1(x+y)=C\cot^{-1}(x + y) = Ccot−1(x+y)=Cd.cot−1(x+y)=x+C\cot^{-1}(x + y) = x + Ccot−1(x+y)=x+CLogin to continueOnly logged in users canattempt or see the solution.
