1.The statement (p∧q)⇒(p∧r)(p \wedge q) \Rightarrow (p \wedge r)(p∧q)⇒(p∧r) is equivalent to:a.q⇒(p∧r)q \Rightarrow (p \wedge r)q⇒(p∧r)b.p⇒(p∧r)p \Rightarrow (p \wedge r)p⇒(p∧r)c.(p∧r)⇒(p∧q)(p \wedge r) \Rightarrow (p \wedge q)(p∧r)⇒(p∧q)d.(p∧q)⇒r(p \wedge q) \Rightarrow r(p∧q)⇒rLogin to continueOnly logged in users canattempt or see the solution.
