1.Let the lines (2−i)z=(2+i)zˉ(2 - i)z = (2 + i)\bar{z}(2−i)z=(2+i)zˉ and (2+i)z+(i−2)zˉ−4i=0(2 + i)z + (i - 2)\bar{z} - 4i = 0(2+i)z+(i−2)zˉ−4i=0 (here i2=−1i^2 = -1i2=−1) be normal to a circle CCC. If the line iz+zˉ+1+i=0iz + \bar{z} + 1 + i = 0iz+zˉ+1+i=0 is tangent to this circle CCC, then its radius is:a.12\dfrac{1}{\sqrt{2}}21b.323\sqrt{2}32c.2\sqrt{2}2d.222Login to continueOnly logged in users canattempt or see the solution.
