1.Let α,β\alpha, \betaα,β be the roots of the equation x2−2 x+6=0x^2 - \sqrt{2}\,x + \sqrt{6} = 0x2−2x+6=0 and 1α+1\dfrac{1}{\alpha} + 1α1+1, 1β+1\dfrac{1}{\beta} + 1β1+1 be the roots of the equation x2+ax+b=0x^2 + ax + b = 0x2+ax+b=0. Then the roots of the equation x2−(a+b−2)x+(a+b+2)=0x^2 - (a + b - 2)x + (a + b + 2) = 0x2−(a+b−2)x+(a+b+2)=0 are:a.non-real complex numbersb.real and both negativec.real and both positived.real and exactly one of them is positiveLogin to continueOnly logged in users canattempt or see the solution.
